bplist00X$versionT$topY$archiverX$objects _columnHeadersDictUpairs_learnVsReviewNumber]formatVersion_cumulativeStudyTime_visibleColumnIdentifiers _NSKeyedArchiver !"#*! 3459O[_`cfgkosv} #$'(037;BEFIJRUY]dghkltw{#&'*+36:>EHILMUX\`gjknowz{U$nullV$classZNS.objectsXdisabledWcolumnAWcolumnBWscoreAB$%&'X$classesZ$classname'()^NSMutableArrayWNSArrayXNSObject+,-0WNS.keys ./ 12 VAnswerXQuestion$%6778)_NSMutableDictionary\NSDictionary;<=>?@ABCDEFGHIJKLMN -6>GPYblt|PQRSTUVWXYZ_performanceDictBAUitemBUitemAXuserDict_performanceDictAB\]^[stringValue_'A sample space is a set that describes $%abb)ZGeniusItem\]e_possible outcomes+,ij +,mn +,qr $%tuu)ZGeniusPairPQRSTUxyz{|\]]An event is a\]_subset of the sample space+, +, +, PQRSTU+#!,%\]"_*The intersection of two events means that \]$[both happen+, &'(*WdueDate[scoreNumberWNS.time)#AK /$%)VNSDate+, +, PQRSTU40.52\]À/_"The union of two events means that\]ǀ1_at least one happens+,΀ &'3*Ӏ)#AK+,׀ +,ۀ PQRSTU<97=;\]8_?@AWSQXU\]DRo5DeMorgan's law states that the complement of A ") B is\]HT_the union of the complements+,LO &'PV*T)#AJ+,WX +,[\ PQRSTU_`abc`\Za^\]f[o,For a probability function P, P(!&) is always\]j]Q1+,nq &'r_*v)#AKA+,yz +,}~ PQRSTUjeckg\]doDFor a probability function P with A and B being disjoint, P(A "* B) =\]f[P(A) + P(B)+, &'hi)#A3+, +, PQRSTUromsq\]no'For any two events A and B, P(A "* B) = \]poP(A) + P(B) " P(A n B)+, +, +, PQRSTU€zwu{y\]ŀv_The P(A') can be defined as\]ɀxX1 - P(A)+,΀ +,Ҁ +,ր PQRSTU݀}\]~_3The conditional probability of R given L is written\]VP(R|L)+, &'*)#AK,E+, +, PQRSTU\]_Given that P(C) > 0, P(A|C) = \]_P(A n C) / P(C)+,  &')#A3w+, +, PQRSTU !"\]%_JThe multiplication rule of conditional probability states that P(A n C) = \])[P(A|C).P(C)+,-0 &'15)#A5T+,89 +,<= PQRSTU@ABCD\]G_^The law of total probability for a sample space consisting of C1 and C2 with event A, P(A) is \]K_P(A|C1).P(C1) + P(A|C2).P(C2)+,OR &'SW)#A7"q 9+,Z[ +,^_ PQRSTUbcdef\]i_Bayes' Rule states that given a series of disjoint events (C1, C2) the conditional probability of Ci given an arbitrary event A is\]m_0P(A|Ci).P(Ci) / P(A) using the total probability+,qt &'uvy)#A4sx+,}~ +, PQRSTU\]_"The event A is independent of B if\]]P(A|B) = P(A)+, +, +, PQRSTU\]_!When A is independent of B, A' is\]_independent of B+, &')#A4vBۃ+, +, "BH"'1:?Xlrbhqx "$+4=DZgpr!#,8:<fot   ,579Vcefgtvwx "*6?GIR[`givxyz#%'02;HJKLY[\]vxz|~ ')*+DFHJLNPY[]       ' ) 2 ? A B C P R S T m o q s u w y         ' 4 6 7 8 E G H I b d f h j l n w y {  ! # ( * , 1 3 5 > @ I V X Y Z g i j k          $ & ( 1 3 < I K L M Z \ ] ^ w y { }   $ & ( 4 A C H J L Q S U ^ ` i v x y z JWYZ[hjkly{|}/13579;DFH~  <EGI[hjoqsxz|3<>@LY[`bdikmvx6?ACcprwy{qz|~  #%')+-/8:<ajln|%249;=BDFOQZgijkxz{|